Who exhibited Georgia O'Keeffe's work at his New York gallery in 1916?
Answer
Alfred Stieglitz
Answer
Alfred Stieglitz
Alfred Stieglitz exhibited Georgia O'Keeffe’s work at his New York gallery in 1916. That presentation helped introduce her abstract drawings to the American art world and began a professional and personal relationship that shaped both careers.
Stieglitz showed O'Keeffe’s charcoal abstractions at his gallery, known first as 291, without her prior permission. He was an influential photographer, dealer, and promoter of modern art. His gallery had already presented European avant-garde artists alongside emerging American artists.
Stieglitz and O'Keeffe married in 1924, although their relationship remained complicated and they often lived apart. Stieglitz photographed O'Keeffe extensively, while she developed an independent reputation through paintings of flowers, landscapes, and bones. The 1916 exhibition is sometimes confused with her later New York solo exhibitions, but it was her first gallery presentation through Stieglitz.
Source: Wikipedia · fact-checked Oct. 2026