Which team did Babe Ruth beat in his 14-inning win in Game 2 of the 1916 World Series?

Babe Ruth beat the Brooklyn Robins in his 14-inning win in Game 2 of the 1916 World Series.

The Robins, now known as the Los Angeles Dodgers, represented the National League, while Ruth’s Boston Red Sox represented the American League. In Game 2, Brooklyn scored first when Hy Myers hit an inside-the-park home run. Boston tied the game in the third inning, with Ruth driving in the run on a ground ball.

The score remained 1–1 through 13 innings. In the bottom of the 14th, Boston won when pinch-hitter Del Gainer delivered a single. Ruth pitched 14 innings and earned the victory, making the game one of the defining pitching performances of his Red Sox career.

The contest set a World Series record for the longest game by innings at the time. Ruth’s pitching was especially notable because his later fame centered on home runs and slugging, yet he was still an elite pitcher in 1916. Boston eventually won the Series in five games, defeating a Brooklyn club whose players and supporters were often called the Robins or, interchangeably, the Dodgers.