Which photographer and gallery owner first exhibited Georgia O'Keeffe's work in 1916?
Answer
Alfred Stieglitz
Answer
Alfred Stieglitz
Alfred Stieglitz first exhibited Georgia O'Keeffe's work in 1916.
Stieglitz showed several of O'Keeffe's abstract charcoal drawings at his New York gallery, 291, without her prior permission. The exhibition introduced her work to an influential American art audience and helped establish her professional reputation.
Stieglitz was a photographer, publisher, and promoter of modern art. His gallery had already presented European and American avant-garde artists, including works that challenged conventional ideas about painting and sculpture. He became deeply interested in O'Keeffe's unusual abstractions.
Their professional relationship became personal. Stieglitz photographed O'Keeffe extensively, and the surviving series contains more than 300 photographs made between 1918 and 1937. They married in 1924, although their relationship was complicated and often involved living apart. O'Keeffe later developed an independent career that extended well beyond Stieglitz's circle.
Source: Wikipedia · fact-checked Oct. 2026