Which gallery owner first exhibited Georgia O'Keeffe's work in New York in 1916?
Answer
Alfred Stieglitz
Answer
Alfred Stieglitz
Alfred Stieglitz first exhibited Georgia O'Keeffe's work in New York in 1916. He showed her charcoal abstractions at his gallery, 291, after receiving them from a friend who had seen her work.
The exhibition introduced O'Keeffe to an influential circle of American modernists. Stieglitz recognized the originality of the drawings and continued to promote her work through his galleries, including the Intimate Gallery and An American Place.
Their professional relationship later became personal, and they married in 1924. William Merritt Chase was one of O'Keeffe's teachers, not the New York gallery owner who first exhibited her work, while Arthur Dove was a fellow modernist rather than her initial promoter.
Source: Wikipedia · fact-checked Sept. 2026