What inequality expresses the second law of thermodynamics for irreversible processes?
Answer
Clausius inequality
Answer
Clausius inequality
The inequality that expresses the second law of thermodynamics for irreversible processes is the Clausius inequality. For a complete thermodynamic cycle, it is commonly written as ∮δQ/T ≤ 0, where δQ is heat transferred to the system and T is the boundary temperature at which that transfer occurs.
Equality holds for a reversible cycle. A strict inequality indicates irreversibility, such as friction, heat flow across a finite temperature difference, turbulence, electrical resistance, or unrestrained expansion. These processes generate entropy and cannot be perfectly reversed without leaving changes in the surroundings.
The result is associated with German physicist Rudolf Clausius, one of the founders of modern thermodynamics. It helped formalize the idea that entropy is a state function and that the total entropy of an isolated system cannot decrease. For a process between two states, the entropy balance is often expressed as ΔS ≥ ∫δQ/T, with the difference representing entropy generation.
The Clausius inequality is distinct from the Kelvin–Planck statement, which describes the impossibility of converting heat from a single reservoir entirely into work. The Clausius–Duhem inequality is a related continuum-mechanics formulation, but it is not the usual answer to this textbook question.
Source: Wikipedia · fact-checked Aug. 2026